This is a most trending question now a days which is going viral and many of the visitors in the internet. So, here we will share with you all the aspects regarding this question and you will got the solution of the question correctly and accurately.
Solution of Tim has a box with a set of 8 green, 5 blue, 6 yellow, and 7 black toys. what is the probability that a random selection would yield a blue or black toy?
In this, they ask the probability of finding blue ball, Here the events are mutually exclusive events, i.e. one event does not influence other event, to be more clear, selection of green ball, does not affects the no. of red and blue balls.
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So, here P(neither red nor green)implies nothing but P(blue balls)
Let n(B)n(B) be no. of blue balls, so n(B)=7n(B)=7
Also, n(S)=n(R)+n(B)+n(G)=8+7+6=21n(S)=n(R)+n(B)+n(G)=8+7+6=21 where n(R),n(B),n(G)n(R),n(B),n(G)are no. of red, blue, green balls respectively.
Then P(B)=n(B)n(S)P(B)=n(B)n(S)
P(B)=721P(B)=721
P(B)=13P(B)=13
i.e. probability of getting neither red or green balls is 1313 or 0.3333…
